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Current Electricity

JEE Main level, single correct, medium

301 of 380

Question 301 of 380

In a meter bridge as shown in the figure, it is given that resistance $Y=12.5\Omega$ and that the balance is obtained at a distance $39.5cm$ from end $A$ (by jockey $J$ ). After interchanging the resistances $X$ and $Y$ a new balance point is found at a distance ${l}_{2}$ from end $A$ . What are the values of $X$ (in $\Omega$ ) and ${l}_{2}$ ?

Show answer and solution

Answer: (B) $8.16\Omega$ and $60.5cm$

For a balanced meter bridge,

(y)\times ​39.5=x\times \left(100-39.5\right)

x=\dfrac{12.5\times 39.5}{60.5}=8.16\Omega

. When

xandy

are interchanged

{l}_{1}

and

(100-{l}_{1})

will also interchange,

{l}_{2}=60.5cm.

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JEE Main 2025 Apr 2 Shift 1 question paper

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