Question 331 of 380

The deflection in moving coil galvanometer falls from $25$ divisions to $5$ division when a shunt of $24\Omega$ is applied. The resistance of galvanometer coil will be:

A$12\Omega$B$96\Omega$C$48\Omega$D$100\Omega$

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Answer: (B) $96\Omega$

Let $x$ represents the current per division though the galvanometer.

After applying shunt

Now, if $G$ is the galvanometer resistance, from the above figure, it can be written that
$5x\times G=20x\times 24 \Rightarrow G=4\times 24 \Rightarrow G=96\Omega$

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