Current Electricity

JEE Main level, single correct, medium

347 of 380

Question 347 of 380

For full scale deflection of total 5050 divisions, 50mV50mV voltage is required in galvanometer. The resistance of galvanometer if its current sensitivity is 2div/mA2div/mA will be:

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Answer: (B) 2Ω2\Omega

C.S.=θIgC.S. =\dfrac{\theta }{{I}_{g}}
Ig=θC.S.=50div2div/mA=25mAIg=\dfrac{\theta }{C.S.}=\dfrac{50div}{2div/mA}=25mA
Potential difference
=50mV=50mV
Resistance
=VI=50mV25mA=2Ω=\dfrac{V}{I}=\dfrac{50mV}{25mA}=2\Omega

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