Current Electricity

JEE Main level, single correct, medium

364 of 380

Question 364 of 380

When a current of 5mA5mA is passed through a galvanometer having a coil of resistance 15Ω15\Omega, it shows full-scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0−10V0-10V is:

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Answer: (B) 1.985×103Ω1.985\times {10}^{3}\Omega

∆V=Ig(Rg+RH)∆V={I}_{g}\left({R}_{g}+{R}_{H}\right)

10=5×10−3{x+15}10=5\times {10}^{-3}\left\{x+15\right\}

x=1.985×103Ωx=1.985\times {10}^{3}\Omega

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