Current Electricity

JEE Main level, single correct, medium

372 of 380

Question 372 of 380

In the circuit diagrams (A, B, C and D) shown below, R\mathrm{R} is a high resistance and S\mathrm{S} is a resistance of the order of galvanometer resistance G. The correct circuit, corresponding to the half deflection method for finding the resistance and figure of merit of the galvanometer, is the circuit labelled as:
(a)

(b)

(C)

(d)

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Answer: (D) Circuit DD with G=RS(R−S)\left.G=\frac{R S}{(R-S}\right)

The correct circuit diagram is DD with galvanometer resistance
G=RSR−SG=\frac{R S}{R-S}

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