Current Electricity

JEE Main level, single correct, medium

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Question 377 of 380

A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 volt, the resistance in ohms needed to be connected in series with the coil will be

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Answer: (D) 9995

Ig=15 mAVg=75mVI_g=15 \mathrm{~mA} \quad V g=75 \mathrm{mV}
R=VIg−VgIg\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}_g}-\frac{\mathrm{V}_g}{I_g}

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