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Experimental Physics

JEE Main level, single correct, medium

56 of 70

Question 56 of 70

The pitch and the number of divisions, on the circular scale, for a given screw gauge are $0.5mm$ and $100$ respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies $3$ divisions below the mean line.

The readings of the main scale and the circular scale, for a thin sheet, are $5.5mm$ and $48$ respectively, the thickness of this sheet is:

Show answer and solution

Answer: (C) $5.725mm$

least count

=\dfrac{0.5mm}{100}=0.005mm

Reading

=5.5mm+\left(48-3\right)\times 0.005mm

=5.725mm.

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JEE Main 2025 Apr 2 Shift 1 question paper

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