Experimental Physics

JEE Main level, single correct, medium

68 of 70

Question 68 of 70

Two full turns of the circular scale of a screw gauge cover a distance of 1 mm1 \mathrm{~mm} on its main scale. The total number of divisions on the circular scale is 50 . Further, it is found that the screw gauge has a zero error of −0.03 mm-0.03 \mathrm{~mm} while measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm3 \mathrm{~mm} and the number of circular scale divisions in line with the main scale as 35 . The diameter of the wire is

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Answer: (D) 3.38 mm3.38 \mathrm{~mm}

Diameter == M.S.R. ++ C.S.R ×\times L.C. ++ Z.E. =3+35×(0.5/50)+0.03=3.38 mm=3+35 \times(0.5 / 50)+0.03=3.38 \mathrm{~mm}

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