Experimental Physics

JEE Main level, single correct, medium

67 of 70

Question 67 of 70

In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree (=0.5∘)\left(=0.5^{\circ}\right), then the least count of the instrument is

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Answer: (A) one minute

 Least count = value of main scale division  No of divisions on vernier scale =130MSD=130×12∘=160∘=1 minute \text { Least count }=\frac{\text { value of main scale division }}{\text { No of divisions on vernier scale }}=\frac{1}{30} \mathrm{MSD}=\frac{1}{30} \times \frac{1}{2}^{\circ}=\frac{1}{60}^{\circ}=1 \text { minute }

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