Gravitation

JEE Main level, single correct, medium

20 of 223

Question 20 of 223

Two stars of masses mm and 2m2m at a distance dd rotate about their common centre of mass in free space. The period of revolution is

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Answer: (A) 2πd33Gm2\pi \sqrt{\dfrac{{d}^{3}}{3Gm}}


F=G(2m)md2=(2m)ω2(d/3)F=\dfrac{G\left(2m\right)m}{{d}^{2}}=\left(2m\right){\omega }^{2}\left(d/3\right)
Gmd2=ω2d3\dfrac{Gm}{{d}^{2}}={\omega }^{2}\dfrac{d}{3}
⇒ω2=3Gmd3\Rightarrow {\omega }^{2}=\dfrac{3Gm}{{d}^{3}}
⇒ω=3Gmd3\Rightarrow \omega =\sqrt{\dfrac{3Gm}{{d}^{3}}}
⇒T=2πω=2πd33Gm\Rightarrow T=\dfrac{2\pi }{\omega }=2\pi \sqrt{\dfrac{{d}^{3}}{3Gm}}

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