Gravitation

JEE Main level, single correct, medium

22 of 223

Question 22 of 223

The mass density of a spherical galaxy varies as Kr\dfrac{K}{r} over a large distance rr from its center. In that region, a small star is in a circular orbit of radius RR. Then the period of revolution,TT depends on RR as:

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Answer: (A) T2∝R{T}^{2}\propto R

M=∫ρdVM=\int \rho dV
M=∫0Rkr4πr2drM={\int }_{0}^{R}\dfrac{k}{r}4\pi {r}^{2}dr
M=4πk∫0RrdrM=4\pi k{\int }_{0}^{R}rdr
M=4πkR22=2πkR2M=\dfrac{4\pi k{R}^{2}}{2}=2\pi k{R}^{2}

FG=GMmR2=mω02R{F}_{G}=\dfrac{GMm}{{R}^{2}}=m{\omega }_{0}^{2}R
⇒G4πkR22R2=ω02R⇒ω0=2πkGR\Rightarrow \dfrac{G\dfrac{4\pi k{R}^{2}}{2}}{{R}^{2}}={\omega }_{0}^{2}R\Rightarrow {\omega }_{0}=\sqrt{\dfrac{2\pi kG}{R}}
∵T=2πω0=2πR2πkG=2πRkG∵T=\dfrac{2\pi }{{\omega }_{0}}=\dfrac{2\pi \sqrt{R}}{\sqrt{2\pi kG}}=\sqrt{\dfrac{2\pi R}{kG}}
⇒T2∝R\Rightarrow {T}^{2}\propto R

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