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Gravitation

JEE Main level, single correct, medium

134 of 223

Question 134 of 223

The minimum and maximum distances of a planet revolving around the Sun are ${x}_{1}$ and ${x}_{2}$ . If the minimum speed of the planet on its trajectory is ${v}_{0}$ , then its maximum speed will be:

Show answer and solution

Answer: (D) $\dfrac{{v}_{0}{x}_{2}}{{x}_{1}}$

Angular momentum conservation equation,

{v}_{0}{x}_{2}={v}_{1}{x}_{1}

{v}_{1}=\dfrac{{v}_{0}{x}_{2}}{{x}_{1}}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Gravitation (Gravitational potential and Potential Energy), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The minimum and maximum distances of a planet revolving around the Sun are x1{x}_{1}x1​ and x2{x}_{2}x2​. If the minimum speed of the planet on its trajectory is v0{v}_{0}v0​, then its maximum speed will be:

JEE Main question paper PDF

More Physics practice

The minimum and maximum distances of a planet revolving around the Sun are ${x}_{1}$ and ${x}_{2}$ . If the minimum speed of the planet on its trajectory is ${v}_{0}$ , then its maximum speed will be: