Gravitation

JEE Main level, single correct, medium

184 of 223

Question 184 of 223

A geostationary satellite is orbiting around an arbitrary planet PP at a height of 11R11R above the surface of PP, RR being the radius of PP. The time period of another satellite in hours at a height of 2R2R from the surface of PP is ________ has the time period of 24hours.24hours.

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Answer: (C) 33

T∝R3/2T\propto {R}^{3/2}
24T=(12R3R)3/2⇒T=3hr\dfrac{24}{T}={\left(\dfrac{12R}{3R}\right)}^{3/2}\Rightarrow T=3hr

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