Gravitation

JEE Main level, single correct, medium

216 of 223

Question 216 of 223

The time period of a satellite in a circular orbit of the radius RR is T.T. The period of another satellite in a circular orbit of the radius 9R9R is:

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Answer: (B) 27T27T

T2∝R3{T}^{2}\propto {R}^{3}.
(T′T)2=(9RR)3{\left(\dfrac{{T}^{'}}{T}\right)}^{2}={\left(\dfrac{9R}{R}\right)}^{3}
T2=T2×93{T}^{2}={T}^{2}\times {9}^{3}
T′=T×33{T}^{'}=T\times {3}^{3}
T′=27T{T}^{'}=27T

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