Kinetic Theory

JEE Main level, single correct, medium

96 of 168

Question 96 of 168


Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature T is:

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Answer: (D) 3RT3RT

The formula of internal energy of a gas is given by
U=f2RTU=\dfrac{f}{2}RT
Here
RR is the gas constant and TT is temperature.
(R=8.314Jmol−1K−1)\left(R=8.314J{mol}^{-1}{K}^{-1}\right)
For the given configuration of triatomic molecules, the degree of freedom
f=6f=6
⇒U=62RT=3RT\Rightarrow U=\dfrac{6}{2}RT=3RT

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