Kinetic Theory

JEE Main level, single correct, medium

145 of 168

Question 145 of 168

What will be the average value of energy for a monoatomic gas in thermal equilibrium at temperature T?T?

Show answer and solution

Answer: (C) 32kBT\dfrac{3}{2}{k}_{B}T

As per Equi-partition law,
each degree of freedom contributes
12kBT\dfrac{1}{2}{k}_{B}T average energy.
In mono atomic gas, D.O.F.D.O.F.=3=3
⇒\Rightarrow Average energy =3×12kBT=32kBT=3\times \dfrac{1}{2}{k}_{B}T=\dfrac{3}{2}{k}_{B}T

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.

More Physics practice

JEE Main Physics practice question on Kinetic Theory (Pressure and Energy of gas), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.