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Kinetic Theory

JEE Main level, single correct, medium

146 of 168

Question 146 of 168

What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature $T?$ ( ${k}_{B}$ is Boltzmann constant)

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Answer: (A) $\dfrac{1}{2}{k}_{B}T$

Energy associated with each degree of freedom per molecule

=\dfrac{1}{2}{k}_{B}T.

Hence, the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature

T=

\dfrac{1}{2}{k}_{B}T.

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Kinetic Theory (Pressure and Energy of gas), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature T?T?T? (kB{k}_{B}kB​ is Boltzmann constant)

JEE Main question paper PDF

More Physics practice

What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature $T?$ ( ${k}_{B}$ is Boltzmann constant)