Laws of Motion

JEE Main level, single correct, medium

12 of 210

Question 12 of 210

A body of mass 4kg4kg experiences two forces F⃗1=5i^+8j^+7k^{\vec{F}}_{1}=5\hat{i}+8\hat{j}+7\hat{k} and F⃗2=3i^−4j^−3k.^{\vec{F}}_{2}=3\hat{i}-4\hat{j}-3\hat{k.} The acceleration acting on the body is:

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Answer: (C) 2i^+j^+k^2\hat{i}+\hat{j}+\hat{k}

Net force F⃗=F⃗1+F⃗2=8i^+4j^+4k^\vec{F}={\vec{F}}_{1}+{\vec{F}}_{2}=8\hat{i}+4\hat{j}+4\hat{k}
Therefore, required acceleration a⃗=F⃗m=2i^+j^+k^\vec{a}=\dfrac{\vec{F}}{m}=2\hat{i}+\hat{j}+\hat{k}

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