Laws of Motion

JEE Main level, single correct, medium

13 of 210

Question 13 of 210

A cricket player catches a ball of mass 120g120g moving with 25ms−125m{s}^{-1} speed. If the catching process is completed in 0.1s0.1s then the magnitude of force exerted by the ball on the hand of player will be(in SI unit):

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Answer: (D) 3030

Average force exerted will be, Fav=∣ΔpΔt∣{F}_{av}=\left|\dfrac{\Delta p}{\Delta t}\right|
=∣0−0.12×250.1∣=30N=\left|\dfrac{0-0.12\times 25}{0.1}\right|=30N

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