Atoms & Nuclei

JEE Main level, numerical answer, medium

225 of 239

Question 225 of 239

Two lighter nuclei combine to form a comparatively heavier nucleus by the relation given below:
X12+X12=Y24X12+X12=Y24
The binding energies per nucleon X12X12 and Y24Y24 are 1.1MeV1.1MeV and 7.6MeV7.6MeV respectively. The energy released in this process is_____ MeVMeV.

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Answer: 26

Energy released in the given process == Binding energy of product −- Binding energy of reactants.
=7.6×4−(1.1×2)×2=7.6\times 4-\left(1.1\times 2\right)\times 2
=30.4−4.4=30.4-4.4
=26MeV=26MeV

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