Semiconductors

JEE Main level, single correct, medium

25 of 209

Question 25 of 209

If the ratio of the concentration of electrons that of holes in a semiconductor is 75\frac{7}{5} and the ratio of currents is 74\frac{7}{4}, then what is the ratio of their drift velocities?

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Answer: (D) 54\frac{5}{4}

nenn=75leln=74\frac{\mathrm{n}_{\mathrm{e}}}{\mathrm{n}_{\mathrm{n}}}=\frac{7}{5} \frac{\mathrm{l}_{\mathrm{e}}}{\mathrm{l}_{\mathrm{n}}}=\frac{7}{4}
(Vd)e(Vd)n⇒leln×nnne=54\frac{\left(\mathrm{V}_{\mathrm{d}}\right)_{\mathrm{e}}}{\left(\mathrm{V}_{\mathrm{d}}\right)_{\mathrm{n}}} \Rightarrow \frac{\mathrm{l}_{\mathrm{e}}}{\mathrm{l}_{\mathrm{n}}} \times \frac{\mathrm{n}_{\mathrm{n}}}{\mathrm{n}_{\mathrm{e}}}=\frac{5}{4}

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