Semiconductors

JEE Main level, single correct, medium

74 of 209

Question 74 of 209

For the circuit shown below, calculate the value of Iz:{I}_{z}:

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Answer: (A) 25mA25mA

I=501000=50mAI=\dfrac{50}{1000}=50mA

I=502000=25mAI=\dfrac{50}{2000}=25mA
IZ=I1000−I2000{I}_{Z}={I}_{1000}-{I}_{2000}
=50−25=25mA=50-25=25mA

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