Semiconductors

JEE Main level, single correct, medium

93 of 209

Question 93 of 209

For the circuit shown below, the current through the Zener diode is

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Answer: (C) 9mA9mA.



Current through
5kΩ5k\Omega,

i1=705000=14mA{i}_{1}=\dfrac{70}{5000}=14mA

Current through
10kΩ10k\Omega,

il=5010000=5mA{i}_{l}=\dfrac{50}{10000}=5mA

Current through the Zener diode,
I=9mAI=9mA

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