Semiconductors

JEE Main level, single correct, medium

103 of 209

Question 103 of 209

A Zener diode is connected to a battery and a load as show below:


The currents, I,IZ\mathrm{I}, \mathrm{I}_{\mathrm{Z}} and IL\mathrm{I}_{\mathrm{L}} are respectively.

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Answer: (D) 12.5 mA,7.5 mA,5 mA12.5 \mathrm{~mA}, 7.5 \mathrm{~mA}, 5 \mathrm{~mA}

Here, R=4kΩ=4×103ΩR=4 \mathrm{k} \Omega=4 \times 10^3 \Omega
Vi=60 VV_i=60 \mathrm{~V}
Zener voltage Vz=10 VV_z=10 \mathrm{~V} RL=2kΩ=2×103ΩR_L=2 \mathrm{k} \Omega=2 \times 10^3 \Omega
Load current, IL=VZRL=102×103=5 mAI_{\mathrm{L}}=\frac{V_Z}{R_L}=\frac{10}{2 \times 10^3}=5 \mathrm{~mA}
Current through R,I=Vi−VZRR, I=\frac{V_i-V_Z}{R} =60−104×103=504×103=12.5 mA=\frac{60-10}{4 \times 10^3}=\frac{50}{4 \times 10^3}=12.5 \mathrm{~mA}
Fom circuit diagram,
I=IZ+IL⇒12.5=IZ+5⇒I7=12.5−5=7.5 mA\begin{aligned} & I=I_Z+I_L \\ \Rightarrow & 12.5=I_Z+5 \\ \Rightarrow & I_7=12.5-5=7.5 \mathrm{~mA} \end{aligned}

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