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Semiconductors

JEE Main level, single correct, medium

105 of 209

Question 105 of 209

Figure shows a circuit in which three identical diodes are used. Each diode has forward resistance of $20 \Omega$ and infinite backward resistance. Resistors $\mathrm{R}_1=\mathrm{R}_2=\mathrm{R}_3=50 \Omega$ . Battery voltage is $6 \mathrm{~V}$ . The current through $\mathrm{R}_3$ is :

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Answer: (A) $50 \mathrm{~mA}$

Here, diodes

D_1

and

D_2

are forward biased and

\mathrm{D}_3

is reverse biased. Therefore current through

\mathrm{R}_3

\mathrm{i}=\frac{\mathrm{V}}{\mathrm{R}^{\prime}}=\frac{6}{120}=\frac{1}{20} \mathrm{~A}=50 \mathrm{~mA}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Semiconductors (Diodes), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.