Semiconductors

JEE Main level, single correct, medium

147 of 209

Question 147 of 209



\begin{array}{c|c|c} A & B & Y \\\hline 0 & 0 & 1 \\0 & 1 & 1 \\1 & 0 & 0 \\1 & 1 & 1\end{array}

To obtain the given truth table, following logic gate should be placed at G:

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Answer: (C) NOR Gate



For NOR gate : AB‾‾=A→+B\overline{\mathrm{A} \overline{\mathrm{B}}}=\overrightarrow{\mathrm{A}}+\mathrm{B}

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