Question 162 of 209

For the logic circuit shown, the output waveform at $Y$ is

ABCD

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Answer: (A)

All the gates used in the diagram represent NAND gates.
Thus, the output $Y$ can be calculated as follows
$\begin{matrix}Y & = & A\cdot B \\ & = & A+B \\ & = & A+B\end{matrix}$
The above equation suggests that the output of the given combination yields the same result as an OR gate.
The truth table can be written as follows $A$ $B$ $A$ $B$ $Y=A\cdot B$ $0$ $0$ $1$ $1$ $0$ $0$ $1$ $1$ $0$ $1$ $1$ $0$ $0$ $1$ $1$ $1$ $1$ $0$ $0$ $1$ Hence, this is the correct output.

JEE Main Physics practice question on Semiconductors (Logic gates), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.