Units & Dimensions

JEE Main level, single correct, medium

113 of 149

Question 113 of 149

A quantity xx is given by (1Fv2/WL4)(1F{v}^{2}/W{L}^{4}) in terms of moment of inertia II, force FF, velocity vv, work WW and length LL. The dimensional formula for xx is same as that of :

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Answer: (C) energy density

IFv2WL4=(M1L2)(M+L1T−2)(L1T−2)2(M1L2T−2)(L4)=M1L−2T−2L3=M4L−1T−2=\dfrac{{IFv}^{2}}{{WL}^{4}}=\dfrac{\left({M}^{1}{L}^{2}\right)\left({M}^{+}{L}^{1}{T}^{-2}\right){\left({L}^{1}{T}^{-2}\right)}^{2}}{\left({M}^{1}{L}^{2}{T}^{-2}\right)\left({L}^{4}\right)}=\dfrac{{M}^{1}{L}^{-2}{T}^{-2}}{{L}^{3}}={M}^{4}{L}^{-1}{T}^{-2}= Energy density

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