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Units & Dimensions

JEE Main level, single correct, medium

114 of 149

Question 114 of 149

Dimensional formula for thermal conductivity is (here $\text{K}$ denotes the temperature):

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Answer: (D) ${\text{MLT}}^{–3}{\text{K}}^{–1}$

k=\dfrac{\left(Q/t\right)\Delta x}{A\Delta T}

=\dfrac{{M}^{1}{L}^{2}{T}^{-2}\left(L\right)}{{L}^{2}K\left(T\right)}={M}^{1}{L}^{1}{T}^{-3}{K}^{-1}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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Units & DimensionsThe dimensional formula of magnetic permeability of free space $\mu_0$ is:
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Units & DimensionsMatch List-I with List-II.
$\begin{array}{ll} \text{List-I} & \text{List-II} \\ \text{(A) Heat capacity of body} & \text{(I) } \mathrm{J} \mathrm{kg}^{-1} \\ \text{(B) Specific heat capacity of body} & \text{(II) } \mathrm{JK}^{-1} \\ \text{(C) Latent heat} & \text{(III) } \mathrm{J} \mathrm{kg}^{-1} \mathrm{~K}^{-1} \\ \text{(D) Thermal conductivity} & \text{(IV) } \mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1} \end{array}$
Choose the correct answer from the options given below :
Units & DimensionsMatch List - I with List - II.

Choose the correct answer from the options given below :
Units & DimensionsMatch List - I with List - II.
$\begin{array}{llll} & \text { List - I } & & \text { List - II } \\ \text { (A) } & \text { Permeability of free space } & \text { (I) }\left[\mathrm{M} \mathrm{~L}^2 \mathrm{~T}^{-2}\right] \\ \text { (B) } & \text { Magnetic field } & \text { (II) }\left[\mathrm{M} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right] \\ \text { (C) } & \text { Magnetic moment } & \text { (III) }\left[\mathrm{M} \mathrm{~L} \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right] \\ \text { (D) } & \text { Torsional constant } & \text { (IV) }\left[\mathrm{L}^2 \mathrm{~A}\right] \end{array}$

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JEE Main Physics practice question on Units & Dimensions (Dimensions), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

Dimensional formula for thermal conductivity is (here K\text{K}K denotes the temperature):

JEE Main question paper PDF

More Physics practice

Dimensional formula for thermal conductivity is (here $\text{K}$ denotes the temperature):