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Units & Dimensions

JEE Main level, single correct, medium

115 of 149

Question 115 of 149

Amount of solar energy received on the earth's surface per unit area per unit time is defined a solar constant. Dimension of solar constant is:

Show answer and solution

Answer: (B) ${ML}^{0}{T}^{-3}$

Solar constant

=\dfrac{Energy}{TimeArea}

=\dfrac{{M}^{1}{L}^{2}{T}^{-2}}{{TL}^{2}}={M}^{1}{L}^{0}{T}^{-3}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

Units & DimensionsThe dimensional formula of magnetic permeability of free space $\mu_0$ is:
Units & DimensionsA new unit $(\alpha)$ of length is chosen such that it is equal to the speed of light in vacuum. What is the distance between Venus and Earth in terms of $\alpha$ units if light takes $6$ min. $40$ s to cover this distance?
Units & DimensionsKeeping the significant figures in view, the sum of the physical quantities $52.01 \mathrm{~m}, 153.2 \mathrm{~m}$ and 0.123 m is :
Units & DimensionsMatch List-I with List-II.
$\begin{array}{ll} \text{List-I} & \text{List-II} \\ \text{(A) Heat capacity of body} & \text{(I) } \mathrm{J} \mathrm{kg}^{-1} \\ \text{(B) Specific heat capacity of body} & \text{(II) } \mathrm{JK}^{-1} \\ \text{(C) Latent heat} & \text{(III) } \mathrm{J} \mathrm{kg}^{-1} \mathrm{~K}^{-1} \\ \text{(D) Thermal conductivity} & \text{(IV) } \mathrm{Jm}^{-1} \mathrm{~K}^{-1} \mathrm{~s}^{-1} \end{array}$
Choose the correct answer from the options given below :
Units & DimensionsMatch List - I with List - II.

Choose the correct answer from the options given below :
Units & DimensionsMatch List - I with List - II.
$\begin{array}{llll} & \text { List - I } & & \text { List - II } \\ \text { (A) } & \text { Permeability of free space } & \text { (I) }\left[\mathrm{M} \mathrm{~L}^2 \mathrm{~T}^{-2}\right] \\ \text { (B) } & \text { Magnetic field } & \text { (II) }\left[\mathrm{M} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right] \\ \text { (C) } & \text { Magnetic moment } & \text { (III) }\left[\mathrm{M} \mathrm{~L} \mathrm{~T}^{-2} \mathrm{~A}^{-2}\right] \\ \text { (D) } & \text { Torsional constant } & \text { (IV) }\left[\mathrm{L}^2 \mathrm{~A}\right] \end{array}$

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JEE Main Physics practice question on Units & Dimensions (Dimensions), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.