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Trigonometry

JEE Main level, single correct, medium

Question 1 of 1

The maximum value of the function $f(x) = 3\sin x + 4\cos x$ is:

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Answer: (C) 5

Maximum of

a\sin x + b\cos x

\sqrt{a^2 + b^2} = \sqrt{3^2 + 4^2} = \sqrt{25} = 5

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Mathematics practice question on Trigonometry, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The maximum value of the function f(x)=3sin⁡x+4cos⁡xf(x) = 3\sin x + 4\cos xf(x)=3sinx+4cosx is:

JEE Main question paper PDF

More Mathematics practice

The maximum value of the function $f(x) = 3\sin x + 4\cos x$ is: