Mathematics · Class 9-10 · CBSE

Quadratic Equations

Aquadratic equationis a polynomial equation of the second degree, meaning it contains at least one term where the variable is squared. These equations are fundamental in mathematics and have wide applications in science and engineering.

1What is a Quadratic Equation?

A quadratic equation in one variable is an equation that can be written in the standard form ax2+bx+c=0ax^2 + bx + c = 0, where aa, bb, and cc are real numbers and a≠0a \neq 0. The highest power of the variable xx is 2.

Components of a Quadratic Equation

  • ax2ax^2

    Description
    The quadratic term (coefficient a≠0a \neq 0)
    Example
    3x23x^2
  • bxbx

    Description
    The linear term (coefficient bb)
    Example
    5x5x
  • cc

    Description
    The constant term
    Example
    −2-2

2Methods to Solve Quadratic Equations

There are several methods to find the values of xx that satisfy a quadratic equation, also known as itsrootsorsolutions. The most common methods are factoring, completing the square, and using the quadratic formula.

Solving by Factoring

  1. 1

    Standard Form

    Rewrite equation as ax2+bx+c=0ax^2 + bx + c = 0

  2. 2

    Factor

    Find two numbers that multiply to acac and add to bb

  3. 3

    Group Terms

    Rewrite bxbx using these numbers and factor by grouping

  4. 4

    Zero Product

    Set each factor to zero and solve for xx

3The Quadratic Formula

Thequadratic formulais a universal method to find the roots of any quadratic equation, regardless of whether it can be factored easily. It directly provides the values of xx.

Quadratic Formula

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
  • xx = roots of the equation
  • a,b,ca, b, c = coefficients from $ax^2 + bx + c = 0$
Common mistake: A common mistake is forgetting to divide the entire numerator by 2a2a, or making sign errors with −b-b and b2−4acb^2 - 4ac.

4Discriminant and Nature of Roots

The expression under the square root in the quadratic formula, b2−4acb^2 - 4ac, is called thediscriminant(Δ\Delta). It tells us about the nature of the roots without actually solving the equation.

5Example: Solving a Quadratic Equation

Real-life example · Solve $2x^2 + 5x - 3 = 0$

Here, a=2a=2, b=5b=5, c=−3c=-3. Using the quadratic formula: x=−5±52−4(2)(−3)2(2)x = \frac{-5 \pm \sqrt{5^2 - 4(2)(-3)}}{2(2)}. This simplifies to x=−5±25+244=−5±494=−5±74x = \frac{-5 \pm \sqrt{25 + 24}}{4} = \frac{-5 \pm \sqrt{49}}{4} = \frac{-5 \pm 7}{4}. So, x1=−5+74=24=12x_1 = \frac{-5 + 7}{4} = \frac{2}{4} = \frac{1}{2} and x2=−5−74=−124=−3x_2 = \frac{-5 - 7}{4} = \frac{-12}{4} = -3. The roots are 1/21/2 and −3-3.

Exam tip: Always check your solutions by substituting them back into the original equation to ensure they satisfy it.

Remember

  • Aquadratic equationis a polynomial of degree 2, written as ax2+bx+c=0ax^2 + bx + c = 0 where a≠0a \neq 0.
  • Therootsor solutions are the values of xx that satisfy the equation.
  • Quadratic equations can be solved byfactoring,completing the square, or using thequadratic formula.
  • Thequadratic formulais x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
  • Thediscriminant, Δ=b2−4ac\Delta = b^2 - 4ac, determines the nature of the roots (real, distinct, or complex).

Check yourself

  1. Question 1

    Which of the following is a quadratic equation?
  2. Question 2

    For the equation x2−4x+4=0x^2 - 4x + 4 = 0, what is the value of the discriminant?
  3. Question 3

    If the discriminant of a quadratic equation is negative, what can be said about its roots?

Read it? Now test it. Timed exam questions on this topic, then a report on what to revise.

Take a test

Want a lesson on another topic? Type any topic or add a photo of your notes — get a lesson like this in seconds.

Learn a topic

More Mathematics explained