Center of Mass, Momentum & Collision

JEE Main level, numerical answer, medium

103 of 130

Question 103 of 130

A ball with a speed of 9ms−19m{s}^{-1} collides with another identical ball at rest. After the collision, the direction of each ball makes an angle of 30∘30^{\circ} with the original direction. If the ratio of velocities of the balls after the collision is x:yx:y, then what is the value of xx?

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Answer: 1


From conservation of momentum along
y−y-axis.
P⃗iy=P⃗fy{\vec{P}}_{iy}={\vec{P}}_{fy}
0+0=mv1sin⁡30∘j^+mv2sin⁡30∘(−j^)0+0=m{v}_{1}\sin 30^{\circ}\hat{j}+m{v}_{2}\sin 30^{\circ}\left(-\hat{j}\right)
mv2sin30∘=mv1sin30∘m{v}_{2}sin30^{\circ}=m{v}_{1}sin30^{\circ}
v2=v1{v}_{2}={v}_{1} or v1v2=1\dfrac{{v}_{1}}{{v}_{2}}=1

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