Question 129 of 130

A mass ' $m$ ' moves with a velocity $v$ and collides inelastically with another identical mass. After collision the $1^{\text {st }}$ mass moves with velocity $v / \sqrt{3}$ in a direction perpendicular to the initial direction of motion. Find the speed of the $2^{\text {nd }}$ mass after collision

AvB$\sqrt{3} v$C$2 v / \sqrt{3}$D$v / \sqrt{3}$

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Answer: (C) $2 v / \sqrt{3}$

$m v=m v_1 \cos \theta$
$0=\frac{m v}{\sqrt{3}}-m v_1 \sin \theta$
$\therefore v_1=\frac{2}{\sqrt{3}} v$