Question 213 of 380

A $16\Omega$ wire is bent to form a square loop. A $9V$ supply having an internal resistance of $1\Omega$ is connected across one of its sides. The potential drop across the diagonals of the square loop is __________$\times {10}^{-1}V$.

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Answer: 45

Here assume current as

By KVL in the outer loop
$9-12i-4i=0$
$16i=9$
$8i=\dfrac{9}{2}=4.5$
$=45\times {10}^{-1}$