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Current Electricity

JEE Main level, single correct, medium

217 of 380

Question 217 of 380

In the given circuit diagram, the currents, ${I}_{1}=-0.3 A, {I}_{4}=0.8 A$ and ${I}_{5}=0.4 A,$ are flowing as shown. The currents ${I}_{2}, {I}_{3}$ and ${I}_{6},$ respectively, are:

Show answer and solution

Answer: (C) $1.1 A, 0.4 A, 0.4 A$

Given{I}_{1}=-0.3A,{I}_{4}=0.8A,{I}_{5}=0.4A, inseriesconnectioncurrentwillbesame,hence{I}_{5}={I}_{6}=0.4A, Accordingtokirchoff'sjuncionrule,algebraicsumofthecurrentsmeetingattthejuctioniszero. i.ecurrentsflowingintothejunctionistakenaspositiveandcurrentflowingoutofthejunctionistakenasnegative. AtthejunctionR, -{I}_{4}+{I}_{2}+{I}_{1}=0 \Rightarrow -0.8+{I}_{2}-0.3=0 \Rightarrow {I}_{2}=1.1A AtjunctionQ, {I}_{6}+{I}_{3}-{I}_{2}-{I}_{1}=0 \Rightarrow 0.4+{I}_{3}-1.1+0.3=0 \Rightarrow {I}_{3}=1.1-0.7=0.4A

It is problem of kirchhof's current law.

{I}_{6}=0.4A

{I}_{3}=0.8A-O.4A=0.4A

{I}_{2}=\left(0.8+0.3\right)A=1.1A

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Current Electricity (Kirchoffs Laws), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

In the given circuit diagram, the currents, I1=−0.3A,I4=0.8A{I}_{1}=-0.3 A, {I}_{4}=0.8 AI1​=−0.3A,I4​=0.8A and I5=0.4A,{I}_{5}=0.4 A,I5​=0.4A, are flowing as shown. The currents I2,I3{I}_{2}, {I}_{3}I2​,I3​ and I6,{I}_{6},I6​, respectively, are:

JEE Main question paper PDF

More Physics practice

In the given circuit diagram, the currents, ${I}_{1}=-0.3 A, {I}_{4}=0.8 A$ and ${I}_{5}=0.4 A,$ are flowing as shown. The currents ${I}_{2}, {I}_{3}$ and ${I}_{6},$ respectively, are: