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Current Electricity

JEE Main level, single correct, medium

269 of 380

Question 269 of 380

A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be

Show answer and solution

Answer: (A) doubled

\mathrm{H}=\frac{\mathrm{V}^2 \Delta \mathrm{t}}{\mathrm{R}}

\mathrm{H}^{\prime}=\frac{\mathrm{V}^2}{\mathrm{R}^{\prime}} \Delta \mathrm{t} \quad

Given

\mathrm{R}^{\prime}=\mathrm{R} / 2

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Current Electricity (Electric Power and Heating Effect of Current), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.