Current Electricity

JEE Main level, single correct, medium

270 of 380

Question 270 of 380

The electrochemical equivalent of a metal is 3.3×10−7 kg3.3 \times 10^{-7} \mathrm{~kg} per coulomb. The mass of the metal liberated at the cathode when a 3 A current is passed for 2 seconds will be

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Answer: (A) 19.8×10−7 kg19.8 \times 10^{-7} \mathrm{~kg}

m=\mathrm{m}= Zit,
m=3.3×10−7×3×2=19.8×10−7 kg\mathrm{m}=3.3 \times 10^{-7} \times 3 \times 2=19.8 \times 10^{-7} \mathrm{~kg}.

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