Question 288 of 380

A battery of $6V$ is connected to the circuit as shown below. The current $I$ drawn from the battery is

A$1A$B$2A$C$\dfrac{6}{11}A$D$\dfrac{4}{3}A$

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Answer: (A) $1A$

The given circuit in the question is a case of a balanced Wheatstone bridge. Therefore, the circuit can be simplified as given below.

The equivalent resistance for the given circuit will be,
${R}_{eq}=\dfrac{\left(3+3\right)\times \left(6+6\right)}{\left(3+3\right)+\left(6+6\right)}+2=6\Omega$
Therefore, the current supplied by the battery is
$i=\dfrac{V}{{R}_{eq}}=\dfrac{6}{6}=1A$

JEE Main Physics practice question on Current Electricity (Wheatstone Bridge), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.