Question 290 of 380

The current $I$ in the given circuit will be

A$10A$B$20A$C$4A$D$40A$

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Answer: (A) $10A$

The circuit can be redrawn as :

We can see that the circuit is a balanced Wheatstone bridge
$\Rightarrow {R}_{AB}=4\Omega$
Current through cell $I=\dfrac{V}{{R}_{AB}}=\dfrac{40}{4}A=10A$

JEE Main Physics practice question on Current Electricity (Wheatstone Bridge), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.