Question 291 of 380

Current measured by the ammeter $\left(A\right)$ in the reported circuit when no current flows through $10\Omega$ resistance, will be _____ $A$.

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Answer: 10

This is a Wheatstone circuit. For the current to be zero in $10\Omega$ the Wheatstone circuit should be balanced. Therefore,
$\dfrac{R}{3}=\dfrac{4}{6}\Rightarrow R=2\Omega$
Now, the equivalent resistance across the battery will be,
${R}_{eq}=\dfrac{\left(2+4\right)\times \left(3+6\right)}{\left(2+4\right)+\left(3+6\right)}=3.6\Omega$
Therefore, the current measured by the ammeter is $i=\dfrac{V}{R}=\dfrac{36}{3.6}=10A$.

JEE Main Physics practice question on Current Electricity (Wheatstone Bridge), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.