Question 333 of 380

Three voltmeters, all having different internal resistances are joined as shown in figure. When some potential difference is applied across $A$ and $B$, their readings are ${V}_{1},{V}_{2}$ and ${V}_{3}$. Choose the correct option.

A${V}_{1}={V}_{2}$B${V}_{1}\neq {V}_{3}-{V}_{2}$C${V}_{1}+{V}_{2}\gt {V}_{3}$D${V}_{1}+{V}_{2}={V}_{3}$

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Answer: (D) ${V}_{1}+{V}_{2}={V}_{3}$

Let's consider the following diagram:

According to the Kirchhoff's voltage law, the algebraic sum of the voltages in a closed loop is zero.
From the above figure, it can be written that
${V}_{1}+{V}_{2}-{V}_{3}=0 \Rightarrow {V}_{1}+{V}_{2}={V}_{3}$