Electrostatics

JEE Main level, single correct, medium

31 of 311

Question 31 of 311

The relative permittivity of distilled water is 81.81. The velocity of light in it will be: ((Given μr=1)\left.{\mu }_{r}=1\right)

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Answer: (C) 3.33×107ms−13.33\times {10}^{7}m{s}^{-1}

V=cμrϵrV=\dfrac{c}{\sqrt{{\mu }_{r}{\epsilon }_{r}}}
=3.33×107msec⁡−1=3.33\times {10}^{7}m{\sec }^{-1}

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