Electrostatics

JEE Main level, single correct, medium

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Question 71 of 311

An infinitely long positively charged straight thread has a linear charge density λCm−1\lambda \mathrm{Cm}^{-1}. An electron revolves along a circular path having axis along the length of the wire. The graph that correctly represents the variation of the kinetic energy of electron as a function of radius of circular path from the wire is :

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Answer: (C)


Electric field
E\mathrm{E} at a distance r\mathrm{r} due to infinite long wire is E=2kλrE=\frac{2 k \lambda}{r}
Force of electron
⇒F=eE\Rightarrow F=e E
$\begin{aligned}

& F=e\left(\frac{2 k \lambda}{r}\right) \\

& F=\frac{2 k \lambda e}{r}

\end{aligned}$

This force will provide required centripetal force

$\begin{aligned}

\mathrm{F} & =\frac{\mathrm{m}^2}{\mathrm{r}}=\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{r}} \\

\mathrm{v} & =\sqrt{\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{m}}} \\

\mathrm{KE} & =\frac{1}{2} \mathrm{mv}^2=\frac{1}{2} \mathrm{~m}\left(\frac{2 \mathrm{k} \lambda \mathrm{e}}{\mathrm{m}}\right) \\

& =\mathrm{k} \lambda \mathrm{e}

\end{aligned}$

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