Electrostatics

JEE Main level, single correct, medium

125 of 311

Question 125 of 311

The region between two concentric spheres of radii 'a' and 'b', respectively (see figure), has volume charge density ρ=Ar\rho =\dfrac{A}{r} , where A is a constant and r is the distance from the centre. At the centre of the spheres is a point charge Q. The value of A such that the electric field in the region between the spheres will be constant, is:

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Answer: (C) Q2πa2\dfrac{Q}{2\pi {a}^{2}}


E=E1+E2{\text{E=E}}_{1}+{\text{E}}_{2}⇒E=K[Q+∫ar4πx2dxAx]r2\Rightarrow E=\dfrac{K\left[Q+\int _{a}^{r}4\pi {x}^{2}dx\dfrac{A}{x}\right]}{{r}^{2}}

E=K[Qr2+4πA{r22r2−a22r2}]E=K\left[\dfrac{Q}{{r}^{2}}+4\pi A\left\{\dfrac{{r}^{2}}{2{r}^{2}}-\dfrac{{a}^{2}}{2{r}^{2}}\right\}\right]

dEdr=0\dfrac{dE}{dr}=0

⇒−2Qr3+8πAa22r3=0\Rightarrow -2\dfrac{Q}{{r}^{3}}+\dfrac{8\pi A{a}^{2}}{2{r}^{3}}=0

A=Q2πa2A=\dfrac{Q}{2\pi {a}^{2}}

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