Question 166 of 311

Two large plane parallel conducting plates are kept 10 cm apart as shown in figure. The potential difference between them is $V$. The potential difference between the points A and B (shown in the figure) is :

A$\frac{1}{4} \mathrm{~V}$B$\frac{2}{5} \mathrm{~V}$C$\frac{3}{4} \mathrm{~V}$D1 V

Show answer and solution▾

Answer: (B) $\frac{2}{5} \mathrm{~V}$

$\begin{aligned} & \text { Using } \Delta V=E(\Delta d) \\ & V=E(10) \\ & V_{A B}=E \cdot 4=\frac{V}{10} \times 4=\frac{2 V}{5}\end{aligned}$