Question 185 of 311

The electric potential at the centre of two concentric half rings of radii ${R}_{1}$ and ${R}_{2}$, having same linear charge density $\lambda$ is
.

A$\dfrac{2\lambda }{{\in }_{0}}$B$\dfrac{\lambda }{2{\in }_{0}}$C$\dfrac{\lambda }{4{\in }_{0}}$D$\dfrac{\lambda }{{\in }_{0}}$

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Answer: (B) $\dfrac{\lambda }{2{\in }_{0}}$

${V}_{O}={V}_{1}+{V}_{2}$
$\Rightarrow {V}_{O}=\dfrac{1}{4\pi {ϵ}_{0}}\times \dfrac{{\lambda }_{1}\left(\pi {R}_{1}\right)}{{R}_{1}}+\dfrac{1}{4\pi {ϵ}_{0}}\times \dfrac{{\lambda }_{1}\left(\pi {R}_{2}\right)}{{R}_{2}} =\dfrac{\lambda }{2{ϵ}_{0}}$

JEE Main Physics practice question on Electrostatics (Electric Potential and Potential Energy), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.