Question 211 of 311

There is a uniform electrostatic field in a region. The potential at various points on a small sphere centred at $P$, in the region, is found to vary between the limits $589.0V$ to $589.8V$. What is the potential at a point on the sphere whose radius vector makes an angle of $60^{\circ}$ with the direction of the field?

A$589.4V$B$589.5V$C$589.2V$D$589.6V$

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Answer: (D) $589.6V$

$\Delta V=Ed$

$Along diameter∆V=589.8-589.0V$
$=0.8V$

$0.8=Ed$

Now

$\Delta V=E\dfrac{d}{2}\cos \theta =0.4\times \cos {60}^{o}$

$=0.2$

$∴589.8-V=0.2$

$V=589.6V$