Electrostatics

JEE Main level, single correct, medium

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Question 230 of 311

Two thin wires rings each having a radius RR are placed at a distance dd apart with their axes coinciding. The charges on the two rings are +q+q and −q-q. The potential difference between the centres of the two rings is

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Answer: (B) Q2πε0[1R−1R2+d2]\frac{Q}{2 \pi \varepsilon_0}\left[\frac{1}{R}-\frac{1}{\sqrt{R^2+d^2}}\right]

v1=kqR−kqR2+d2v_1=\frac{k q}{R}-\frac{k q}{\sqrt{R^2+d^2}}
v2=−kqR+kqR2+d2v_2=\frac{-k q}{R}+\frac{k q}{\sqrt{R^2+d^2}}

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