Electrostatics

JEE Main level, numerical answer, medium

247 of 311

Question 247 of 311

The electric field at point p\mathrm{p} due to an electric dipole is E\mathrm{E}. The electric field at point R\mathrm{R} on equitorial line will be Ex\frac{\mathrm{E}}{x}. The value of xx :

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Answer: 16

EP=2KPr3=EER=KP(2r)3=E16x=16\begin{aligned} & E_P=\frac{2 K P}{r^3}=E \\ & E_R=\frac{K P}{(2 r)^3}=\frac{E}{16} \\ & x=16\end{aligned}

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